3.2.45 \(\int (f+g x)^{3/2} (a+b \log (c (d+e x)^n))^2 \, dx\) [145]

Optimal. Leaf size=590 \[ \frac {368 b^2 (e f-d g)^2 n^2 \sqrt {f+g x}}{75 e^2 g}+\frac {128 b^2 (e f-d g) n^2 (f+g x)^{3/2}}{225 e g}+\frac {16 b^2 n^2 (f+g x)^{5/2}}{125 g}-\frac {368 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{75 e^{5/2} g}-\frac {8 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )^2}{5 e^{5/2} g}-\frac {8 b (e f-d g)^2 n \sqrt {f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^2 g}-\frac {8 b (e f-d g) n (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{15 e g}-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}+\frac {8 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^{5/2} g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}+\frac {16 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \log \left (\frac {2}{1-\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}}\right )}{5 e^{5/2} g}+\frac {8 b^2 (e f-d g)^{5/2} n^2 \text {Li}_2\left (1-\frac {2}{1-\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}}\right )}{5 e^{5/2} g} \]

[Out]

128/225*b^2*(-d*g+e*f)*n^2*(g*x+f)^(3/2)/e/g+16/125*b^2*n^2*(g*x+f)^(5/2)/g-368/75*b^2*(-d*g+e*f)^(5/2)*n^2*ar
ctanh(e^(1/2)*(g*x+f)^(1/2)/(-d*g+e*f)^(1/2))/e^(5/2)/g-8/5*b^2*(-d*g+e*f)^(5/2)*n^2*arctanh(e^(1/2)*(g*x+f)^(
1/2)/(-d*g+e*f)^(1/2))^2/e^(5/2)/g-8/15*b*(-d*g+e*f)*n*(g*x+f)^(3/2)*(a+b*ln(c*(e*x+d)^n))/e/g-8/25*b*n*(g*x+f
)^(5/2)*(a+b*ln(c*(e*x+d)^n))/g+8/5*b*(-d*g+e*f)^(5/2)*n*arctanh(e^(1/2)*(g*x+f)^(1/2)/(-d*g+e*f)^(1/2))*(a+b*
ln(c*(e*x+d)^n))/e^(5/2)/g+2/5*(g*x+f)^(5/2)*(a+b*ln(c*(e*x+d)^n))^2/g+16/5*b^2*(-d*g+e*f)^(5/2)*n^2*arctanh(e
^(1/2)*(g*x+f)^(1/2)/(-d*g+e*f)^(1/2))*ln(2/(1-e^(1/2)*(g*x+f)^(1/2)/(-d*g+e*f)^(1/2)))/e^(5/2)/g+8/5*b^2*(-d*
g+e*f)^(5/2)*n^2*polylog(2,1-2/(1-e^(1/2)*(g*x+f)^(1/2)/(-d*g+e*f)^(1/2)))/e^(5/2)/g+368/75*b^2*(-d*g+e*f)^2*n
^2*(g*x+f)^(1/2)/e^2/g-8/5*b*(-d*g+e*f)^2*n*(a+b*ln(c*(e*x+d)^n))*(g*x+f)^(1/2)/e^2/g

________________________________________________________________________________________

Rubi [A]
time = 1.54, antiderivative size = 590, normalized size of antiderivative = 1.00, number of steps used = 28, number of rules used = 15, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.577, Rules used = {2445, 2458, 2388, 65, 214, 2390, 12, 1601, 6873, 6131, 6055, 2449, 2352, 2356, 52} \begin {gather*} \frac {8 b^2 n^2 (e f-d g)^{5/2} \text {PolyLog}\left (2,1-\frac {2}{1-\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}}\right )}{5 e^{5/2} g}+\frac {8 b n (e f-d g)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^{5/2} g}-\frac {8 b n \sqrt {f+g x} (e f-d g)^2 \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^2 g}-\frac {8 b n (f+g x)^{3/2} (e f-d g) \left (a+b \log \left (c (d+e x)^n\right )\right )}{15 e g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}-\frac {8 b^2 n^2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )^2}{5 e^{5/2} g}-\frac {368 b^2 n^2 (e f-d g)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{75 e^{5/2} g}+\frac {16 b^2 n^2 (e f-d g)^{5/2} \log \left (\frac {2}{1-\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}}\right ) \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{5 e^{5/2} g}+\frac {368 b^2 n^2 \sqrt {f+g x} (e f-d g)^2}{75 e^2 g}+\frac {128 b^2 n^2 (f+g x)^{3/2} (e f-d g)}{225 e g}+\frac {16 b^2 n^2 (f+g x)^{5/2}}{125 g} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(f + g*x)^(3/2)*(a + b*Log[c*(d + e*x)^n])^2,x]

[Out]

(368*b^2*(e*f - d*g)^2*n^2*Sqrt[f + g*x])/(75*e^2*g) + (128*b^2*(e*f - d*g)*n^2*(f + g*x)^(3/2))/(225*e*g) + (
16*b^2*n^2*(f + g*x)^(5/2))/(125*g) - (368*b^2*(e*f - d*g)^(5/2)*n^2*ArcTanh[(Sqrt[e]*Sqrt[f + g*x])/Sqrt[e*f
- d*g]])/(75*e^(5/2)*g) - (8*b^2*(e*f - d*g)^(5/2)*n^2*ArcTanh[(Sqrt[e]*Sqrt[f + g*x])/Sqrt[e*f - d*g]]^2)/(5*
e^(5/2)*g) - (8*b*(e*f - d*g)^2*n*Sqrt[f + g*x]*(a + b*Log[c*(d + e*x)^n]))/(5*e^2*g) - (8*b*(e*f - d*g)*n*(f
+ g*x)^(3/2)*(a + b*Log[c*(d + e*x)^n]))/(15*e*g) - (8*b*n*(f + g*x)^(5/2)*(a + b*Log[c*(d + e*x)^n]))/(25*g)
+ (8*b*(e*f - d*g)^(5/2)*n*ArcTanh[(Sqrt[e]*Sqrt[f + g*x])/Sqrt[e*f - d*g]]*(a + b*Log[c*(d + e*x)^n]))/(5*e^(
5/2)*g) + (2*(f + g*x)^(5/2)*(a + b*Log[c*(d + e*x)^n])^2)/(5*g) + (16*b^2*(e*f - d*g)^(5/2)*n^2*ArcTanh[(Sqrt
[e]*Sqrt[f + g*x])/Sqrt[e*f - d*g]]*Log[2/(1 - (Sqrt[e]*Sqrt[f + g*x])/Sqrt[e*f - d*g])])/(5*e^(5/2)*g) + (8*b
^2*(e*f - d*g)^(5/2)*n^2*PolyLog[2, 1 - 2/(1 - (Sqrt[e]*Sqrt[f + g*x])/Sqrt[e*f - d*g])])/(5*e^(5/2)*g)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 52

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^n/(b*(
m + n + 1))), x] + Dist[n*((b*c - a*d)/(b*(m + n + 1))), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 65

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 214

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x/Rt[-a/b, 2]], x] /; FreeQ[{a, b},
x] && NegQ[a/b]

Rule 1601

Int[(Pp_)/(Qq_), x_Symbol] :> With[{p = Expon[Pp, x], q = Expon[Qq, x]}, Simp[Coeff[Pp, x, p]*(Log[RemoveConte
nt[Qq, x]]/(q*Coeff[Qq, x, q])), x] /; EqQ[p, q - 1] && EqQ[Pp, Simplify[(Coeff[Pp, x, p]/(q*Coeff[Qq, x, q]))
*D[Qq, x]]]] /; PolyQ[Pp, x] && PolyQ[Qq, x]

Rule 2352

Int[Log[(c_.)*(x_)]/((d_) + (e_.)*(x_)), x_Symbol] :> Simp[(-e^(-1))*PolyLog[2, 1 - c*x], x] /; FreeQ[{c, d, e
}, x] && EqQ[e + c*d, 0]

Rule 2356

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_) + (e_.)*(x_))^(q_.), x_Symbol] :> Simp[(d + e*x)^(q + 1)
*((a + b*Log[c*x^n])^p/(e*(q + 1))), x] - Dist[b*n*(p/(e*(q + 1))), Int[((d + e*x)^(q + 1)*(a + b*Log[c*x^n])^
(p - 1))/x, x], x] /; FreeQ[{a, b, c, d, e, n, p, q}, x] && GtQ[p, 0] && NeQ[q, -1] && (EqQ[p, 1] || (Integers
Q[2*p, 2*q] &&  !IGtQ[q, 0]) || (EqQ[p, 2] && NeQ[q, 1]))

Rule 2388

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_) + (e_.)*(x_))^(q_.))/(x_), x_Symbol] :> Dist[d, Int[(d
+ e*x)^(q - 1)*((a + b*Log[c*x^n])^p/x), x], x] + Dist[e, Int[(d + e*x)^(q - 1)*(a + b*Log[c*x^n])^p, x], x] /
; FreeQ[{a, b, c, d, e, n}, x] && IGtQ[p, 0] && GtQ[q, 0] && IntegerQ[2*q]

Rule 2390

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_) + (e_.)*(x_)^(r_.))^(q_.))/(x_), x_Symbol] :> With[{u = IntHi
de[(d + e*x^r)^q/x, x]}, Simp[u*(a + b*Log[c*x^n]), x] - Dist[b*n, Int[Dist[1/x, u, x], x], x]] /; FreeQ[{a, b
, c, d, e, n, r}, x] && IntegerQ[q - 1/2]

Rule 2445

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)*((f_.) + (g_.)*(x_))^(q_.), x_Symbol] :> Simp[(f
+ g*x)^(q + 1)*((a + b*Log[c*(d + e*x)^n])^p/(g*(q + 1))), x] - Dist[b*e*n*(p/(g*(q + 1))), Int[(f + g*x)^(q
+ 1)*((a + b*Log[c*(d + e*x)^n])^(p - 1)/(d + e*x)), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, q}, x] && NeQ[e*
f - d*g, 0] && GtQ[p, 0] && NeQ[q, -1] && IntegersQ[2*p, 2*q] && ( !IGtQ[q, 0] || (EqQ[p, 2] && NeQ[q, 1]))

Rule 2449

Int[Log[(c_.)/((d_) + (e_.)*(x_))]/((f_) + (g_.)*(x_)^2), x_Symbol] :> Dist[-e/g, Subst[Int[Log[2*d*x]/(1 - 2*
d*x), x], x, 1/(d + e*x)], x] /; FreeQ[{c, d, e, f, g}, x] && EqQ[c, 2*d] && EqQ[e^2*f + d^2*g, 0]

Rule 2458

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_.) + (g_.)*(x_))^(q_.)*((h_.) + (i_.)*(x_))
^(r_.), x_Symbol] :> Dist[1/e, Subst[Int[(g*(x/e))^q*((e*h - d*i)/e + i*(x/e))^r*(a + b*Log[c*x^n])^p, x], x,
d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, h, i, n, p, q, r}, x] && EqQ[e*f - d*g, 0] && (IGtQ[p, 0] || IGtQ[
r, 0]) && IntegerQ[2*r]

Rule 6055

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)/((d_) + (e_.)*(x_)), x_Symbol] :> Simp[(-(a + b*ArcTanh[c*x])^p)
*(Log[2/(1 + e*(x/d))]/e), x] + Dist[b*c*(p/e), Int[(a + b*ArcTanh[c*x])^(p - 1)*(Log[2/(1 + e*(x/d))]/(1 - c^
2*x^2)), x], x] /; FreeQ[{a, b, c, d, e}, x] && IGtQ[p, 0] && EqQ[c^2*d^2 - e^2, 0]

Rule 6131

Int[(((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)*(x_))/((d_) + (e_.)*(x_)^2), x_Symbol] :> Simp[(a + b*ArcTanh[c
*x])^(p + 1)/(b*e*(p + 1)), x] + Dist[1/(c*d), Int[(a + b*ArcTanh[c*x])^p/(1 - c*x), x], x] /; FreeQ[{a, b, c,
d, e}, x] && EqQ[c^2*d + e, 0] && IGtQ[p, 0]

Rule 6873

Int[u_, x_Symbol] :> With[{v = NormalizeIntegrand[u, x]}, Int[v, x] /; v =!= u]

Rubi steps

\begin {align*} \int (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2 \, dx &=\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}-\frac {(4 b e n) \int \frac {(f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{d+e x} \, dx}{5 g}\\ &=\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}-\frac {(4 b n) \text {Subst}\left (\int \frac {\left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^{5/2} \left (a+b \log \left (c x^n\right )\right )}{x} \, dx,x,d+e x\right )}{5 g}\\ &=\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}-\frac {(4 b n) \text {Subst}\left (\int \left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^{3/2} \left (a+b \log \left (c x^n\right )\right ) \, dx,x,d+e x\right )}{5 e}-\frac {(4 b (e f-d g) n) \text {Subst}\left (\int \frac {\left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x} \, dx,x,d+e x\right )}{5 e g}\\ &=-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}-\frac {(4 b (e f-d g) n) \text {Subst}\left (\int \sqrt {\frac {e f-d g}{e}+\frac {g x}{e}} \left (a+b \log \left (c x^n\right )\right ) \, dx,x,d+e x\right )}{5 e^2}-\frac {\left (4 b (e f-d g)^2 n\right ) \text {Subst}\left (\int \frac {\sqrt {\frac {e f-d g}{e}+\frac {g x}{e}} \left (a+b \log \left (c x^n\right )\right )}{x} \, dx,x,d+e x\right )}{5 e^2 g}+\frac {\left (8 b^2 n^2\right ) \text {Subst}\left (\int \frac {\left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^{5/2}}{x} \, dx,x,d+e x\right )}{25 g}\\ &=\frac {16 b^2 n^2 (f+g x)^{5/2}}{125 g}-\frac {8 b (e f-d g) n (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{15 e g}-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}-\frac {\left (4 b (e f-d g)^2 n\right ) \text {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{\sqrt {\frac {e f-d g}{e}+\frac {g x}{e}}} \, dx,x,d+e x\right )}{5 e^3}-\frac {\left (4 b (e f-d g)^3 n\right ) \text {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{x \sqrt {\frac {e f-d g}{e}+\frac {g x}{e}}} \, dx,x,d+e x\right )}{5 e^3 g}+\frac {\left (8 b^2 (e f-d g) n^2\right ) \text {Subst}\left (\int \frac {\left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^{3/2}}{x} \, dx,x,d+e x\right )}{25 e g}+\frac {\left (8 b^2 (e f-d g) n^2\right ) \text {Subst}\left (\int \frac {\left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^{3/2}}{x} \, dx,x,d+e x\right )}{15 e g}\\ &=\frac {128 b^2 (e f-d g) n^2 (f+g x)^{3/2}}{225 e g}+\frac {16 b^2 n^2 (f+g x)^{5/2}}{125 g}-\frac {8 b (e f-d g)^2 n \sqrt {f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^2 g}-\frac {8 b (e f-d g) n (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{15 e g}-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}+\frac {8 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^{5/2} g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}+\frac {\left (8 b^2 (e f-d g)^2 n^2\right ) \text {Subst}\left (\int \frac {\sqrt {\frac {e f-d g}{e}+\frac {g x}{e}}}{x} \, dx,x,d+e x\right )}{25 e^2 g}+\frac {\left (8 b^2 (e f-d g)^2 n^2\right ) \text {Subst}\left (\int \frac {\sqrt {\frac {e f-d g}{e}+\frac {g x}{e}}}{x} \, dx,x,d+e x\right )}{15 e^2 g}+\frac {\left (8 b^2 (e f-d g)^2 n^2\right ) \text {Subst}\left (\int \frac {\sqrt {\frac {e f-d g}{e}+\frac {g x}{e}}}{x} \, dx,x,d+e x\right )}{5 e^2 g}+\frac {\left (4 b^2 (e f-d g)^3 n^2\right ) \text {Subst}\left (\int -\frac {2 \sqrt {e} \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f-\frac {d g}{e}+\frac {g x}{e}}}{\sqrt {e f-d g}}\right )}{\sqrt {e f-d g} x} \, dx,x,d+e x\right )}{5 e^3 g}\\ &=\frac {368 b^2 (e f-d g)^2 n^2 \sqrt {f+g x}}{75 e^2 g}+\frac {128 b^2 (e f-d g) n^2 (f+g x)^{3/2}}{225 e g}+\frac {16 b^2 n^2 (f+g x)^{5/2}}{125 g}-\frac {8 b (e f-d g)^2 n \sqrt {f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^2 g}-\frac {8 b (e f-d g) n (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{15 e g}-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}+\frac {8 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^{5/2} g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}-\frac {\left (8 b^2 (e f-d g)^{5/2} n^2\right ) \text {Subst}\left (\int \frac {\tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f-\frac {d g}{e}+\frac {g x}{e}}}{\sqrt {e f-d g}}\right )}{x} \, dx,x,d+e x\right )}{5 e^{5/2} g}+\frac {\left (8 b^2 (e f-d g)^3 n^2\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {\frac {e f-d g}{e}+\frac {g x}{e}}} \, dx,x,d+e x\right )}{25 e^3 g}+\frac {\left (8 b^2 (e f-d g)^3 n^2\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {\frac {e f-d g}{e}+\frac {g x}{e}}} \, dx,x,d+e x\right )}{15 e^3 g}+\frac {\left (8 b^2 (e f-d g)^3 n^2\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {\frac {e f-d g}{e}+\frac {g x}{e}}} \, dx,x,d+e x\right )}{5 e^3 g}\\ &=\frac {368 b^2 (e f-d g)^2 n^2 \sqrt {f+g x}}{75 e^2 g}+\frac {128 b^2 (e f-d g) n^2 (f+g x)^{3/2}}{225 e g}+\frac {16 b^2 n^2 (f+g x)^{5/2}}{125 g}-\frac {8 b (e f-d g)^2 n \sqrt {f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^2 g}-\frac {8 b (e f-d g) n (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{15 e g}-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}+\frac {8 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^{5/2} g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}-\frac {\left (16 b^2 (e f-d g)^{5/2} n^2\right ) \text {Subst}\left (\int \frac {x \tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {e f-d g}}\right )}{d g+e \left (-f+x^2\right )} \, dx,x,\sqrt {f+g x}\right )}{5 e^{3/2} g}+\frac {\left (16 b^2 (e f-d g)^3 n^2\right ) \text {Subst}\left (\int \frac {1}{-\frac {e f-d g}{g}+\frac {e x^2}{g}} \, dx,x,\sqrt {f+g x}\right )}{25 e^2 g^2}+\frac {\left (16 b^2 (e f-d g)^3 n^2\right ) \text {Subst}\left (\int \frac {1}{-\frac {e f-d g}{g}+\frac {e x^2}{g}} \, dx,x,\sqrt {f+g x}\right )}{15 e^2 g^2}+\frac {\left (16 b^2 (e f-d g)^3 n^2\right ) \text {Subst}\left (\int \frac {1}{-\frac {e f-d g}{g}+\frac {e x^2}{g}} \, dx,x,\sqrt {f+g x}\right )}{5 e^2 g^2}\\ &=\frac {368 b^2 (e f-d g)^2 n^2 \sqrt {f+g x}}{75 e^2 g}+\frac {128 b^2 (e f-d g) n^2 (f+g x)^{3/2}}{225 e g}+\frac {16 b^2 n^2 (f+g x)^{5/2}}{125 g}-\frac {368 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{75 e^{5/2} g}-\frac {8 b (e f-d g)^2 n \sqrt {f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^2 g}-\frac {8 b (e f-d g) n (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{15 e g}-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}+\frac {8 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^{5/2} g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}-\frac {\left (16 b^2 (e f-d g)^{5/2} n^2\right ) \text {Subst}\left (\int \frac {x \tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {e f-d g}}\right )}{-e f+d g+e x^2} \, dx,x,\sqrt {f+g x}\right )}{5 e^{3/2} g}\\ &=\frac {368 b^2 (e f-d g)^2 n^2 \sqrt {f+g x}}{75 e^2 g}+\frac {128 b^2 (e f-d g) n^2 (f+g x)^{3/2}}{225 e g}+\frac {16 b^2 n^2 (f+g x)^{5/2}}{125 g}-\frac {368 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{75 e^{5/2} g}-\frac {8 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )^2}{5 e^{5/2} g}-\frac {8 b (e f-d g)^2 n \sqrt {f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^2 g}-\frac {8 b (e f-d g) n (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{15 e g}-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}+\frac {8 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^{5/2} g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}+\frac {\left (16 b^2 (e f-d g)^2 n^2\right ) \text {Subst}\left (\int \frac {\tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {e f-d g}}\right )}{1-\frac {\sqrt {e} x}{\sqrt {e f-d g}}} \, dx,x,\sqrt {f+g x}\right )}{5 e^2 g}\\ &=\frac {368 b^2 (e f-d g)^2 n^2 \sqrt {f+g x}}{75 e^2 g}+\frac {128 b^2 (e f-d g) n^2 (f+g x)^{3/2}}{225 e g}+\frac {16 b^2 n^2 (f+g x)^{5/2}}{125 g}-\frac {368 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{75 e^{5/2} g}-\frac {8 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )^2}{5 e^{5/2} g}-\frac {8 b (e f-d g)^2 n \sqrt {f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^2 g}-\frac {8 b (e f-d g) n (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{15 e g}-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}+\frac {8 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^{5/2} g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}+\frac {16 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \log \left (\frac {2}{1-\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}}\right )}{5 e^{5/2} g}-\frac {\left (16 b^2 (e f-d g)^2 n^2\right ) \text {Subst}\left (\int \frac {\log \left (\frac {2}{1-\frac {\sqrt {e} x}{\sqrt {e f-d g}}}\right )}{1-\frac {e x^2}{e f-d g}} \, dx,x,\sqrt {f+g x}\right )}{5 e^2 g}\\ &=\frac {368 b^2 (e f-d g)^2 n^2 \sqrt {f+g x}}{75 e^2 g}+\frac {128 b^2 (e f-d g) n^2 (f+g x)^{3/2}}{225 e g}+\frac {16 b^2 n^2 (f+g x)^{5/2}}{125 g}-\frac {368 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{75 e^{5/2} g}-\frac {8 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )^2}{5 e^{5/2} g}-\frac {8 b (e f-d g)^2 n \sqrt {f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^2 g}-\frac {8 b (e f-d g) n (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{15 e g}-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}+\frac {8 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^{5/2} g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}+\frac {16 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \log \left (\frac {2}{1-\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}}\right )}{5 e^{5/2} g}+\frac {\left (16 b^2 (e f-d g)^{5/2} n^2\right ) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1-\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}}\right )}{5 e^{5/2} g}\\ &=\frac {368 b^2 (e f-d g)^2 n^2 \sqrt {f+g x}}{75 e^2 g}+\frac {128 b^2 (e f-d g) n^2 (f+g x)^{3/2}}{225 e g}+\frac {16 b^2 n^2 (f+g x)^{5/2}}{125 g}-\frac {368 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )}{75 e^{5/2} g}-\frac {8 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )^2}{5 e^{5/2} g}-\frac {8 b (e f-d g)^2 n \sqrt {f+g x} \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^2 g}-\frac {8 b (e f-d g) n (f+g x)^{3/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{15 e g}-\frac {8 b n (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )}{25 g}+\frac {8 b (e f-d g)^{5/2} n \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{5 e^{5/2} g}+\frac {2 (f+g x)^{5/2} \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{5 g}+\frac {16 b^2 (e f-d g)^{5/2} n^2 \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right ) \log \left (\frac {2}{1-\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}}\right )}{5 e^{5/2} g}+\frac {8 b^2 (e f-d g)^{5/2} n^2 \text {Li}_2\left (1-\frac {2}{1-\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}}\right )}{5 e^{5/2} g}\\ \end {align*}

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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
time = 4.29, size = 1143, normalized size = 1.94 \begin {gather*} \frac {2 \left (\frac {15 b^2 n^2 \sqrt {f+g x} \left (10 g (-e f+d g) (d+e x) \, _4F_3\left (-\frac {3}{2},1,1,1;2,2,2;\frac {g (d+e x)}{-e f+d g}\right )-15 d^2 g^2 \, _4F_3\left (-\frac {1}{2},1,1,1;2,2,2;\frac {g (d+e x)}{-e f+d g}\right )-15 d e g^2 x \, _4F_3\left (-\frac {1}{2},1,1,1;2,2,2;\frac {g (d+e x)}{-e f+d g}\right )+4 e^2 f^2 \log (d+e x)-8 d e f g \log (d+e x)+4 d^2 g^2 \log (d+e x)-4 e^2 f^2 \sqrt {\frac {e (f+g x)}{e f-d g}} \log (d+e x)-8 e^2 f g x \sqrt {\frac {e (f+g x)}{e f-d g}} \log (d+e x)-4 e^2 g^2 x^2 \sqrt {\frac {e (f+g x)}{e f-d g}} \log (d+e x)+15 d^2 g^2 \, _3F_2\left (-\frac {1}{2},1,1;2,2;\frac {g (d+e x)}{-e f+d g}\right ) \log (d+e x)+15 d e g^2 x \, _3F_2\left (-\frac {1}{2},1,1;2,2;\frac {g (d+e x)}{-e f+d g}\right ) \log (d+e x)+2 e^2 f^2 \log ^2(d+e x)+d e f g \log ^2(d+e x)-3 d^2 g^2 \log ^2(d+e x)-2 e^2 f^2 \sqrt {\frac {e (f+g x)}{e f-d g}} \log ^2(d+e x)+e^2 f g x \sqrt {\frac {e (f+g x)}{e f-d g}} \log ^2(d+e x)+3 e^2 g^2 x^2 \sqrt {\frac {e (f+g x)}{e f-d g}} \log ^2(d+e x)-10 g (-e f+d g) (d+e x) \, _3F_2\left (-\frac {3}{2},1,1;2,2;\frac {g (d+e x)}{-e f+d g}\right ) (1+\log (d+e x))\right )}{e^2 \sqrt {\frac {e (f+g x)}{e f-d g}}}+\frac {75 b^2 f n^2 \sqrt {f+g x} \left (3 g (d+e x) \, _4F_3\left (-\frac {1}{2},1,1,1;2,2,2;\frac {g (d+e x)}{-e f+d g}\right )+\log (d+e x) \left (-3 g (d+e x) \, _3F_2\left (-\frac {1}{2},1,1;2,2;\frac {g (d+e x)}{-e f+d g}\right )+\left (d g+e g x \sqrt {\frac {e (f+g x)}{e f-d g}}+e f \left (-1+\sqrt {\frac {e (f+g x)}{e f-d g}}\right )\right ) \log (d+e x)\right )\right )}{e \sqrt {\frac {e (f+g x)}{e f-d g}}}-\frac {50 b f n \left (6 (e f-d g)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )+\sqrt {e} \sqrt {f+g x} (6 d g-2 e (4 f+g x)+3 e (f+g x) \log (d+e x))\right ) \left (-a+b n \log (d+e x)-b \log \left (c (d+e x)^n\right )\right )}{e^{3/2}}+\frac {2 b n \left (30 \sqrt {e f-d g} \left (2 e^2 f^2+d e f g-3 d^2 g^2\right ) \tanh ^{-1}\left (\frac {\sqrt {e} \sqrt {f+g x}}{\sqrt {e f-d g}}\right )+\sqrt {e} \sqrt {f+g x} \left (90 d^2 g^2-30 d e g (2 f+g x)+2 e^2 \left (-31 f^2+8 f g x+9 g^2 x^2\right )+15 e^2 \left (2 f^2-f g x-3 g^2 x^2\right ) \log (d+e x)\right )\right ) \left (-a+b n \log (d+e x)-b \log \left (c (d+e x)^n\right )\right )}{e^{5/2}}+45 (f+g x)^{5/2} \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^2\right )}{225 g} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(f + g*x)^(3/2)*(a + b*Log[c*(d + e*x)^n])^2,x]

[Out]

(2*((15*b^2*n^2*Sqrt[f + g*x]*(10*g*(-(e*f) + d*g)*(d + e*x)*HypergeometricPFQ[{-3/2, 1, 1, 1}, {2, 2, 2}, (g*
(d + e*x))/(-(e*f) + d*g)] - 15*d^2*g^2*HypergeometricPFQ[{-1/2, 1, 1, 1}, {2, 2, 2}, (g*(d + e*x))/(-(e*f) +
d*g)] - 15*d*e*g^2*x*HypergeometricPFQ[{-1/2, 1, 1, 1}, {2, 2, 2}, (g*(d + e*x))/(-(e*f) + d*g)] + 4*e^2*f^2*L
og[d + e*x] - 8*d*e*f*g*Log[d + e*x] + 4*d^2*g^2*Log[d + e*x] - 4*e^2*f^2*Sqrt[(e*(f + g*x))/(e*f - d*g)]*Log[
d + e*x] - 8*e^2*f*g*x*Sqrt[(e*(f + g*x))/(e*f - d*g)]*Log[d + e*x] - 4*e^2*g^2*x^2*Sqrt[(e*(f + g*x))/(e*f -
d*g)]*Log[d + e*x] + 15*d^2*g^2*HypergeometricPFQ[{-1/2, 1, 1}, {2, 2}, (g*(d + e*x))/(-(e*f) + d*g)]*Log[d +
e*x] + 15*d*e*g^2*x*HypergeometricPFQ[{-1/2, 1, 1}, {2, 2}, (g*(d + e*x))/(-(e*f) + d*g)]*Log[d + e*x] + 2*e^2
*f^2*Log[d + e*x]^2 + d*e*f*g*Log[d + e*x]^2 - 3*d^2*g^2*Log[d + e*x]^2 - 2*e^2*f^2*Sqrt[(e*(f + g*x))/(e*f -
d*g)]*Log[d + e*x]^2 + e^2*f*g*x*Sqrt[(e*(f + g*x))/(e*f - d*g)]*Log[d + e*x]^2 + 3*e^2*g^2*x^2*Sqrt[(e*(f + g
*x))/(e*f - d*g)]*Log[d + e*x]^2 - 10*g*(-(e*f) + d*g)*(d + e*x)*HypergeometricPFQ[{-3/2, 1, 1}, {2, 2}, (g*(d
+ e*x))/(-(e*f) + d*g)]*(1 + Log[d + e*x])))/(e^2*Sqrt[(e*(f + g*x))/(e*f - d*g)]) + (75*b^2*f*n^2*Sqrt[f + g
*x]*(3*g*(d + e*x)*HypergeometricPFQ[{-1/2, 1, 1, 1}, {2, 2, 2}, (g*(d + e*x))/(-(e*f) + d*g)] + Log[d + e*x]*
(-3*g*(d + e*x)*HypergeometricPFQ[{-1/2, 1, 1}, {2, 2}, (g*(d + e*x))/(-(e*f) + d*g)] + (d*g + e*g*x*Sqrt[(e*(
f + g*x))/(e*f - d*g)] + e*f*(-1 + Sqrt[(e*(f + g*x))/(e*f - d*g)]))*Log[d + e*x])))/(e*Sqrt[(e*(f + g*x))/(e*
f - d*g)]) - (50*b*f*n*(6*(e*f - d*g)^(3/2)*ArcTanh[(Sqrt[e]*Sqrt[f + g*x])/Sqrt[e*f - d*g]] + Sqrt[e]*Sqrt[f
+ g*x]*(6*d*g - 2*e*(4*f + g*x) + 3*e*(f + g*x)*Log[d + e*x]))*(-a + b*n*Log[d + e*x] - b*Log[c*(d + e*x)^n]))
/e^(3/2) + (2*b*n*(30*Sqrt[e*f - d*g]*(2*e^2*f^2 + d*e*f*g - 3*d^2*g^2)*ArcTanh[(Sqrt[e]*Sqrt[f + g*x])/Sqrt[e
*f - d*g]] + Sqrt[e]*Sqrt[f + g*x]*(90*d^2*g^2 - 30*d*e*g*(2*f + g*x) + 2*e^2*(-31*f^2 + 8*f*g*x + 9*g^2*x^2)
+ 15*e^2*(2*f^2 - f*g*x - 3*g^2*x^2)*Log[d + e*x]))*(-a + b*n*Log[d + e*x] - b*Log[c*(d + e*x)^n]))/e^(5/2) +
45*(f + g*x)^(5/2)*(a - b*n*Log[d + e*x] + b*Log[c*(d + e*x)^n])^2))/(225*g)

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Maple [F]
time = 0.18, size = 0, normalized size = 0.00 \[\int \left (g x +f \right )^{\frac {3}{2}} \left (a +b \ln \left (c \left (e x +d \right )^{n}\right )\right )^{2}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((g*x+f)^(3/2)*(a+b*ln(c*(e*x+d)^n))^2,x)

[Out]

int((g*x+f)^(3/2)*(a+b*ln(c*(e*x+d)^n))^2,x)

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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^(3/2)*(a+b*log(c*(e*x+d)^n))^2,x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(4*%e^2*f-4*%e*d*g>0)', see `as
sume?` for m

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^(3/2)*(a+b*log(c*(e*x+d)^n))^2,x, algorithm="fricas")

[Out]

integral((b^2*g*x + b^2*f)*sqrt(g*x + f)*log((x*e + d)^n*c)^2 + 2*(a*b*g*x + a*b*f)*sqrt(g*x + f)*log((x*e + d
)^n*c) + (a^2*g*x + a^2*f)*sqrt(g*x + f), x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (a + b \log {\left (c \left (d + e x\right )^{n} \right )}\right )^{2} \left (f + g x\right )^{\frac {3}{2}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)**(3/2)*(a+b*ln(c*(e*x+d)**n))**2,x)

[Out]

Integral((a + b*log(c*(d + e*x)**n))**2*(f + g*x)**(3/2), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((g*x+f)^(3/2)*(a+b*log(c*(e*x+d)^n))^2,x, algorithm="giac")

[Out]

integrate((g*x + f)^(3/2)*(b*log((x*e + d)^n*c) + a)^2, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\left (f+g\,x\right )}^{3/2}\,{\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right )}^2 \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((f + g*x)^(3/2)*(a + b*log(c*(d + e*x)^n))^2,x)

[Out]

int((f + g*x)^(3/2)*(a + b*log(c*(d + e*x)^n))^2, x)

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